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Sign in to iCloud to access your photos, videos, documents, notes, contacts, and more Use your Apple ID or create a new account to start using Apple servicesWhen Q = 0, C = 190, so fixed cost is equal to 190 (or $1,900,000) b If the company produced 100,000 units of goods, what is its average variable cost?Learn vocabulary, terms, and more with flashcards, games, and other study tools
1(YT) I = b 0 b 1Y b 2i Md/P = Ca*i G = G 0 T = T 0 Ms = M 0 All the parameters (a, b 0,b 1, b 2, c 1) in the model are positive, and b 1 c 1B A a y I "y" Shear Force z x y V y "x" Shear Force z x y V x τ τ τ = ⋅ ⋅ ⋅ V A y I b b a g Note The maximum shear stress for common cross sections are Cross Section Cross Section Rectangular τmax = 3 2 ⋅V A Solid Circular τmax = 4 3 ⋅V A IBeam or HBeam flange web τmax = V A web Thinwalled tube τmax = 2 ⋅ V AWith 100,000 units, Q = 10 Variable cost is 53Q = (53)(10) = 530 (or $5,300,000) Average variable cost is
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We now sub in our value for Y from (b) and our value for T given in the question C = 0 025(1000 – 0) C = 0 025(800) C = 400 Investment is given as I = 150 025Y – 1000i We sub in our values for i and Y from (b) I = 150 025(1000) – 1000(005) I = 150 250 – 50 I = 350 The second part of the question asks us to verifyQ= adjacent cot opposite q= Unit circle definition For this definition q is any angle sin 1 y q==y 1 csc y q= cos 1 x q==x 1 sec x q= tan y x q= cot x y q= Facts and Properties Domain The domain is all the values of q that can be plugged into the function sinq, q can be any angle cosq, q can be any angle tanq, 1,0,1,2, 2 qpnn æö „ç÷
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5 5 A 1 = p Q 1 C Q 1 = 65*45 *45 = 2,025 , A 2 = p Q 2 C Q 2 C = 80*30 *30 = 1,350 If firm 1 breaks the cartel producing 45, instead of 30, it realizes profits equal to $2,025, while if it stays in the cartel, it realizes profits equal to $ 1,800Q B = y¿A¿=(0025)(003) = 9375A106B m3 Q A = 0 I = 1 12 (003) A0053B = A106B m4 9–33 The clamp bears down on the smooth surface at E by tightening the bolt If the tensile force in the bolt is 40 kN, determine the principal stress at points A and B andThe force on the wire is given by F = IL × B The direction of L × B is the negative ydirection Since L and B are perpendicular to each other, the magnitude F = ILB Details of the calculation F = ILB = (24 A)(075 m)(16 T) = 2 N The force on the section of wire is F = 2 N j, in the negative y
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