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Cos (x) = −1 cos ( x) = 1 Take the inverse cosine of both sides of the equation to extract x x from inside the cosine x = arccos(−1) x = arccos ( 1) The exact value of arccos(−1) arccos ( 1) is π π x = π x = π The cosine function is negative in the second and third quadrants To find the second solution, subtract the©05 BE Shapiro Page 3 This document may not be reproduced, posted or published without permission The copyright holder makes no representation about the accuracy, correctness, orSolution Comparing this problem with the formulas stated in the rule on integration formulas resulting in inverse trigonometric functions, the integrand looks similar to the formula for tan −1 u C tan −1 u C So we use substitution, letting u = 2 x, u = 2 x, then d u = 2 d x d u = 2 d x and 1 Cos inverse 1-x^2/1+x^2 formula

Intuitively, a function is a process that associates each element of a set X, to a single element of a set Y Formally, a function f from a set X to a set Y is defined by a set G of ordered pairs (x, y) with x ∈ X, y ∈ Y, such that every element of X is the first component of exactly one ordered pair in G In other words, for every x in X, there is exactly one element y such that theA b v f g W _ E h i N C A g j y W ł B O v E F A desknet's( f X N l b c) ͎g ₷ O Nj A X P W Ǘ Ō I ɏ ` B A 񋤗L i ߂ c ł B08 i j N ̗Վ ԁE C x g ԂȂ V O O O n p m } J A ^ s I B e F Q O O W N P Q Q U The Fundamental Theorem Of Calculus "òs‹@ Ž_'fƒ}ƒXƒN ƒCƒ‰ƒXƒg

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